225+x^2=(2x)^2

Solution for 225+x^2=(2x)^2 equation:

225+x^2=(2x)^2

We move all terms to the left:

225+x^2-((2x)^2)=0

determiningTheFunctionDomain
x^2-2x^2+225=0

We add all the numbers together, and all the variables

-1x^2+225=0

a = -1; b = 0; c = +225;
Δ = b2-4ac
Δ = 02-4·(-1)·225
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*-1}=\frac{-30}{-2}
=+15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*-1}=\frac{30}{-2}
=-15
$